The 8051 Microcontroller and Embedded Systems, Volume 1For courses teaching the 8051 Microcontoller. This book uses a step-by-step approach to teach the fundamentals of assembly language programming and interfacing of the 8051 microcontroller. It uses many examples to clarify concepts. Simple, concise examples are utilized to show what action each instruction performs, then a sample is provided to show its application. This text provides a comprehensive understanding of the internal organization of the 8051 registers and resources in a way that sheds the student's fear of assembly language. Whether students become designers of stand-alone systems or complex embedded systems, they will find this text a useful resource. |
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Page 67
... loop can be repeated a maximum of 256 times . Loop inside a loop As shown in Example 3-2 , the maximum count is 256. What happens if we want to repeat an action more times than 256 ? To do that , we use a loop inside a loop , which is ...
... loop can be repeated a maximum of 256 times . Loop inside a loop As shown in Example 3-2 , the maximum count is 256. What happens if we want to repeat an action more times than 256 ? To do that , we use a loop inside a loop , which is ...
Page 78
... loop and ignore the clock cycles associated with the instructions outside the loop . In Example 3-15 , the largest value the R3 register can take is 255 ; there- fore , one way to increase the delay is to use NOP instructions in the loop ...
... loop and ignore the clock cycles associated with the instructions outside the loop . In Example 3-15 , the largest value the R3 register can take is 255 ; there- fore , one way to increase the delay is to use NOP instructions in the loop ...
Page 79
... loop , we have ( 4 × 250 ) 1.085 μs = 1085 μs . The AGAIN loop repeats the HERE loop 200 times ; therefore , we have 200 × 1085 μs = 217000 , if we do not include the overhead . However , the instructions " MOV R3 , # 250 " and " DJNZ ...
... loop , we have ( 4 × 250 ) 1.085 μs = 1085 μs . The AGAIN loop repeats the HERE loop 200 times ; therefore , we have 200 × 1085 μs = 217000 , if we do not include the overhead . However , the instructions " MOV R3 , # 250 " and " DJNZ ...
Contents
CHAPTERS | 1 |
The 8051 Microcontrollers | 23 |
THE 8051 MICROCONTROLLERS 223 Section 1 1 Microcontrollers and Embedded Processors | 24 |
Copyright | |
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Other editions - View all
The 8051 Microcontroller And Embedded Systems Using Assembly And C, 2/E Muhammad Ali Mazidi,Mazidi No preview available - 2007 |
Common terms and phrases
ACALL ACALL DELAY addr addressing mode ASCII Assembly language baud rate binary bit addresses carry flag Chapter CJNE connected convert data pins decimal decoder discussed DJNZ DPTR EPROM Example execution external interrupt Figure flag bit frequency I/O ports instruction INT1 Intel interfacing interrupt vector table jump latch LCALL LJMP load logic loop machine cycle memory chip memory location microcontroller microprocessor MOV P1 MOV RO MOVX Notice NV-RAM on-chip ROM opcode operand output pointer program counter PSEN pull-up resistors pulse RAM location register bank reset Review Questions SBUF SECTION serial communication SETB TR1 Show signal SJMP Solution square wave stack stepper motor stop bit SUBB subroutine target address TCON timer Timer/counter TMOD transfer transistors True or false voltage Write a program