The 8051 Microcontroller and Embedded Systems, Volume 1For courses teaching the 8051 Microcontoller. This book uses a step-by-step approach to teach the fundamentals of assembly language programming and interfacing of the 8051 microcontroller. It uses many examples to clarify concepts. Simple, concise examples are utilized to show what action each instruction performs, then a sample is provided to show its application. This text provides a comprehensive understanding of the internal organization of the 8051 registers and resources in a way that sheds the student's fear of assembly language. Whether students become designers of stand-alone systems or complex embedded systems, they will find this text a useful resource. |
From inside the book
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Page 52
... Solution : 38 00111000 + 2F 00101111 67 01100111 CY = 0 since there is no carry beyond the D7 bit AC = 1 since there is a carry from the D3 to the D4 bit P = 1 since the accumulator has an odd number of 1s ( it has five 1s ) . Example 2 ...
... Solution : 38 00111000 + 2F 00101111 67 01100111 CY = 0 since there is no carry beyond the D7 bit AC = 1 since there is a carry from the D3 to the D4 bit P = 1 since the accumulator has an odd number of 1s ( it has five 1s ) . Example 2 ...
Page 103
... solution ( b ) that there are two instructions that are repeated numerous times . We can create a loop with those two instructions as shown in solution ( c ) . Solution ( c ) is the most efficient and is possible only because of ...
... solution ( b ) that there are two instructions that are repeated numerous times . We can create a loop with those two instructions as shown in solution ( c ) . Solution ( c ) is the most efficient and is possible only because of ...
Page 129
... Solution : 04H 0000 0100 68H 0110 1000 6CH 0110 1100 04 OR 68 = 6CH XOR XRL destination , source X XOR Y X Y 0 0 0 0 1 1 1 0 1 1 1 0 ; dest = dest XOR source This instruction will perform the XOR operation on the two operands , and ...
... Solution : 04H 0000 0100 68H 0110 1000 6CH 0110 1100 04 OR 68 = 6CH XOR XRL destination , source X XOR Y X Y 0 0 0 0 1 1 1 0 1 1 1 0 ; dest = dest XOR source This instruction will perform the XOR operation on the two operands , and ...
Contents
CHAPTERS | 1 |
The 8051 Microcontrollers | 23 |
THE 8051 MICROCONTROLLERS 2323 Section 1 1 Microcontrollers and Embedded Processors | 24 |
Copyright | |
19 other sections not shown
Other editions - View all
The 8051 Microcontroller And Embedded Systems Using Assembly And C, 2/E Muhammad Ali Mazidi,Mazidi No preview available - 2007 |
Common terms and phrases
ACALL ACALL DELAY addr addressing mode ASCII Assembly language baud rate binary bit addresses carry flag Chapter CJNE connected convert data pins decimal decoder discussed DJNZ DPTR EPROM Example execution external interrupt Figure flag bit frequency I/O ports instruction INT1 Intel interfacing interrupt vector table jump latch LCALL LJMP load logic loop machine cycle memory chip memory location microcontroller microprocessor MOV P1 MOV RO MOVX Notice NV-RAM on-chip ROM opcode operand output pointer program counter PSEN pull-up resistors pulse RAM location register bank reset Review Questions SBUF SECTION serial communication SETB TR1 Show signal SJMP Solution square wave stack stepper motor stop bit SUBB subroutine target address TCON timer Timer/counter TMOD transistors True or false voltage Write a program