Introduction to Operations ResearchCD-ROM contains: Student version of MPL Modeling System and its solver CPLEX -- MPL tutorial -- Examples from the text modeled in MPL -- Examples from the text modeled in LINGO/LINDO -- Tutorial software -- Excel add-ins: TreePlan, SensIt, RiskSim, and Premium Solver -- Excel spreadsheet formulations and templates. |
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Page 760
0.25 ( 0.6 ) = 0.15 Oil and FSS 0.15 0.5 0.3 Oil , given FSS 0.6 FSS , given Oil 0.4 USS , given Oil 0.1 = 0.14 0.7 Oil , given USS 1 0.25 ( 0.4 ) = 0.1 Oil and USS 0.25 Oil 0.75 Dry 0.75 ( 0.2 ) = 0.15 Dry and FSS 0.15 : 0.5 0.3 Dry ...
0.25 ( 0.6 ) = 0.15 Oil and FSS 0.15 0.5 0.3 Oil , given FSS 0.6 FSS , given Oil 0.4 USS , given Oil 0.1 = 0.14 0.7 Oil , given USS 1 0.25 ( 0.4 ) = 0.1 Oil and USS 0.25 Oil 0.75 Dry 0.75 ( 0.2 ) = 0.15 Dry and FSS 0.15 : 0.5 0.3 Dry ...
Page 786
What is the resulting ( e ) Given that the research is done , use your answers in parts ( c ) expected payoff ( excluding the payment ) ? and ( d ) to determine the posterior probabilities of the states of ( f ) If you have the ...
What is the resulting ( e ) Given that the research is done , use your answers in parts ( c ) expected payoff ( excluding the payment ) ? and ( d ) to determine the posterior probabilities of the states of ( f ) If you have the ...
Page 999
Consider a one - period model where the only two costs are the holding cost , given by h ( y – D ) = ( y – D ) , for y = D , I 19.7-4 . Solve Prob . 19.7-3 for a two - period model , assuming no salvage value , no backlogging at the end ...
Consider a one - period model where the only two costs are the holding cost , given by h ( y – D ) = ( y – D ) , for y = D , I 19.7-4 . Solve Prob . 19.7-3 for a two - period model , assuming no salvage value , no backlogging at the end ...
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Contents
SUPPLEMENT TO APPENDIX 3 | 3 |
Problems | 6 |
SUPPLEMENT TO CHAPTER | 18 |
Copyright | |
52 other sections not shown
Other editions - View all
Introduction to Operations Research Frederick S. Hillier,Gerald J. Lieberman No preview available - 2001 |
Common terms and phrases
activity additional algorithm allocation allowable amount apply assignment basic solution basic variable BF solution bound boundary called changes coefficients column complete Consider constraint Construct corresponding cost CPF solution decision variables demand described determine distribution dual problem entering equal equations estimates example feasible feasible region feasible solutions FIGURE final flow formulation functional constraints given gives goal identify illustrate increase indicates initial iteration linear programming Maximize million Minimize month needed node nonbasic variables objective function obtained operations optimal optimal solution original parameters path plant possible presented primal problem Prob procedure profit programming problem provides range remaining resource respective resulting revised shown shows side simplex method simplex tableau slack solve step supply Table tableau tion unit values weeks Wyndor Glass zero