Further Engineering Mathematics: Programmes and ProblemsThe purpose of this book is essentially to provide a sound second year course in mathematics appropriate to studies leading to BSc Engineering degrees. It is a companion volume to "Engineering Mathematics" which is for the first year. An ELBS edition is available. |
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Results 1-3 of 18
Page 108
... δυ cos 2y for ( 3 ) x ecos y : ( 4 ) x e * sin y : Adding : e ̄ * cos y du = cos2y dx - sin y cos y dy e * sin yov = - sin2 ydx + sin y cos y dy e ̄ * cos you + e * sin y dv = ( cos2 y - sin2 y ) dx But .. δε = e- * cos y · cos y Su + ...
... δυ cos 2y for ( 3 ) x ecos y : ( 4 ) x e * sin y : Adding : e ̄ * cos y du = cos2y dx - sin y cos y dy e * sin yov = - sin2 ydx + sin y cos y dy e ̄ * cos you + e * sin y dv = ( cos2 y - sin2 y ) dx But .. δε = e- * cos y · cos y Su + ...
Page 537
... δυ ди ди u ) . ( c ) Similarly for S1 , since u is constant along P1S1 du = 0 and ду δυ ( x + 0000 , X + 20000 ) .. S1 is the point ( x + y So the cartesian coordinates of P1 , Q1 , S1 are P1 ( x , y ) ; ax дх dv Sv , ду δυ 2 : ( x + 3x ...
... δυ ди ди u ) . ( c ) Similarly for S1 , since u is constant along P1S1 du = 0 and ду δυ ( x + 0000 , X + 20000 ) .. S1 is the point ( x + y So the cartesian coordinates of P1 , Q1 , S1 are P1 ( x , y ) ; ax дх dv Sv , ду δυ 2 : ( x + 3x ...
Page 538
... δυ x + ах бо до ди ду ду y y + δυ y + δυ dv ди Subtracting column 1 from columns 2 and 3 gives 1 0 0 dx дх δυ δι Area = 1-2 Χ du dv ду δι y ди 12 212 dy δυ which simplifies immediately to h . 59 дх дх δυ δι dv 1 ди Area = 2 ду би ду δυ ...
... δυ x + ах бо до ди ду ду y y + δυ y + δυ dv ди Subtracting column 1 from columns 2 and 3 gives 1 0 0 dx дх δυ δι Area = 1-2 Χ du dv ду δι y ди 12 212 dy δυ which simplifies immediately to h . 59 дх дх δυ δι dv 1 ди Area = 2 ду би ду δυ ...
Contents
Theory of Equations Part 2 | 43 |
Partial Differentiation | 91 |
Integral Functions | 145 |
Copyright | |
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a₁ b₁ b₂ c₁ c₂ coefficients cosh cosine curl F curve curvilinear coordinates defined Determine dx dy dx² dy dx Evaluate exact differential Example expression F.dr Fourier series frame function f(x function values gives grad graph Green's theorem harmonic inverse transforms k₁ k₂ Laplace transform line integral matrix method nx dx obtain odd function parametric equations partial fractions Pdx Qdy periodic function plane polar coordinates programme region Revision Summary roots scalar sin nx sin² sinh solution Solve the equation stationary values substitute surface Test Exercise theorem U₁ variables vector field w-plane x₁ xy-plane Y₁ zero δε δυ бу дг дг ди ди др ду ди ду ду дф дф дх ду дг მა